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4x^2+6x-88=0
a = 4; b = 6; c = -88;
Δ = b2-4ac
Δ = 62-4·4·(-88)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-38}{2*4}=\frac{-44}{8} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+38}{2*4}=\frac{32}{8} =4 $
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